If it's not what You are looking for type in the equation solver your own equation and let us solve it.
13x^2=90
We move all terms to the left:
13x^2-(90)=0
a = 13; b = 0; c = -90;
Δ = b2-4ac
Δ = 02-4·13·(-90)
Δ = 4680
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4680}=\sqrt{36*130}=\sqrt{36}*\sqrt{130}=6\sqrt{130}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{130}}{2*13}=\frac{0-6\sqrt{130}}{26} =-\frac{6\sqrt{130}}{26} =-\frac{3\sqrt{130}}{13} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{130}}{2*13}=\frac{0+6\sqrt{130}}{26} =\frac{6\sqrt{130}}{26} =\frac{3\sqrt{130}}{13} $
| (5x)+(2x)=90 | | -2a-5=3(5-2a) | | 3k+38=92 | | (60)+(4x)=90 | | 13–8x=141 | | 3(-2x+4)=-6x-12* | | 20=48t^2 | | 3s+4.75=21 | | 93/4−2s=21/4 | | x=74x≥13 | | 5=-1-7/k | | (4x+9)(5x+5)=180 | | 3(x+4)=-3* | | x^2-14x=287 | | 9x=135* | | 10(s-9)=-172 | | c/5c+5=30 | | x+4+x-5=90 | | -8x+8+3x-6=-3x+2 | | -8x+8+3x-6=-3x+2*4 | | -8-11x10=30 | | 7y+46=5(y+6) | | 2(3s+6)=60 | | -12x-15=-3(2x+3)* | | m+12=3m+4 | | -6(x-1)=-3-12 | | 4x-6=-5(x-6) | | 8x-3°=180° | | 22.5=x1.5 | | 1.5=x22.5 | | 104n+(-84n)=36 | | 16=5(v+4)-3v |